Sun's quadratic-character conjecture for Dp(3)D_p^{(3)}

From papers

For positive integers m,nm,n with nn odd, define

Dn(m)=det[(j2k2)m(j2k2n)]1j,k(n1)/2.D_n^{(m)}=\det\left[(j^2-k^2)^m\left(\frac{j^2-k^2}n\right)\right]_{1\leqslant j,k\leqslant(n-1)/2}.

For primes p1(mod4)p\equiv1\pmod4, this determinant is an integer square, so choose a square root Dp(3)\sqrt{D_p^{(3)}}. Sun's quadratic-character conjecture. For every prime p1(mod4)p\equiv1\pmod4,

(Dp(3)p)=(1){0<k<p4:(kp)=1}(p4+(1)(p1)/4).\left(\frac{\sqrt{D_p^{(3)}}}p\right)=(-1)^{\left|\left\{0<k<\frac p4:\left(\frac kp\right)=-1\right\}\right|}\left(\frac p{4+(-1)^{(p-1)/4}}\right).

The source reports verification for all primes p<1000p<1000 with p1(mod4)p\equiv1\pmod4, but gives no proof or resolution.

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Sources & referencesView supporting material

Primary source

Zhi-Wei Sun, “Some determinants involving quadratic residues modulo primes”, arXiv:2401.14301 (2024).

Additional references

5 papers in this index state this conjecture (2020–2024). The statement above is taken from the most recent of them; the others are arXiv:2305.16064, arXiv:2210.16826, arXiv:2108.10624, arXiv:2012.05746.

Solutions 0

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