Defant and Zheng's maximal-time conjecture for the consecutive-pattern-avoiding stack-sorting map
Let be the set of permutations of length , let be the stack-sorting map whose stack avoids consecutive occurrences of , and let denote the set of permutations in avoiding and consecutively. Defant and Zheng's conjecture. For any permutation of length ,
Also, for every , there exists for which
The paper states this as a conjecture of Defant and Zheng and presents a counterexample, so the asserted universal claim is refuted; the first displayed bound is instead proved in the paper's main theorem.
References
Primary source
Ilaria Seidel and Nathan Sun, “Periodic Points of Consecutive-Pattern-Avoiding Stack-Sorting Maps”, arXiv:2308.05868 (2023).
Progress summary
A 2023 counterexample disproves the conjectured linear-time bound, while newer computations give only broader bounds and leave the true growth rate open.
Defant and Zheng conjectured that every permutation reaches the consecutive-pattern-avoiding set after iterations, with this bound sharp. Seidel and Sun found a length- counterexample, so the universal assertion is false.
Known results
- The conjecture was verified for by Defant and Zheng.
- Seidel and Sun exhibited , which reaches a periodic point only after iterations, whereas .
- Seidel and Sun proved the general upper bound , where is the maximum sort-number.
- Periodic points are exactly the permutations avoiding and its reverse consecutively, and all have period .
April 2026 computational study
A paper by Seidel and Sun computes sort-numbers through length and estimates averages through length . It proves an lower bound and the upper bound , while reported data suggest faster-than-linear growth; the asymptotic behavior remains unclear.
Current status (as of September 2026): The universal conjecture is refuted by a published counterexample, but the exact maximum sort-number and its growth rate remain open.
Sources
Solutions 0
No solutions have been posted yet.