Defant and Zheng's maximal-time conjecture for the consecutive-pattern-avoiding stack-sorting map

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Let SnS_n be the set of permutations of length nn, let SC231:Sn→SnSC_{231}:S_n\to S_n be the stack-sorting map whose stack avoids consecutive occurrences of 231231, and let Av⁡n(132,231)\operatorname{Av}_n(132,231) denote the set of permutations in SnS_n avoiding 132132 and 231231 consecutively. Defant and Zheng's conjecture. For any permutation π\pi of length n≥3n\geq 3,

SC2312n−4(π)∈Av⁡n(132,231).SC_{231}^{2n-4}(\pi)\in \operatorname{Av}_n(132,231).

Also, for every n≥3n\geq 3, there exists τ∈Sn\tau\in S_n for which

SC2312n−5(τ)∉Av⁡n(132,231).SC_{231}^{2n-5}(\tau)\notin \operatorname{Av}_n(132,231).

The paper states this as a conjecture of Defant and Zheng and presents a counterexample, so the asserted universal claim is refuted; the first displayed bound is instead proved in the paper's main theorem.

References

Primary source

Ilaria Seidel and Nathan Sun, “Periodic Points of Consecutive-Pattern-Avoiding Stack-Sorting Maps”, arXiv:2308.05868 (2023).

Progress summary

Refreshed
Claimed solved

A 2023 counterexample disproves the conjectured linear-time bound, while newer computations give only broader bounds and leave the true growth rate open.

Defant and Zheng conjectured that every permutation reaches the consecutive-pattern-avoiding set after 2n−42n-4 iterations, with this bound sharp. Seidel and Sun found a length-1111 counterexample, so the universal assertion is false.

Known results

  • The conjecture was verified for n≤9n\leq 9 by Defant and Zheng.
  • Seidel and Sun exhibited (4,6,8,5,11,7,2,9,10,3,1)(4,6,8,5,11,7,2,9,10,3,1), which reaches a periodic point only after 1919 iterations, whereas 2n−4=182n-4=18.
  • Seidel and Sun proved the general upper bound f(n)≤(n−1)(n−2)f(n)\leq(n-1)(n-2), where f(n)f(n) is the maximum sort-number.
  • Periodic points are exactly the permutations avoiding 231231 and its reverse consecutively, and all have period 22.

April 2026 computational study

A paper by Seidel and Sun computes sort-numbers through length 1414 and estimates averages through length 10001000. It proves an (n−1)(n-1) lower bound and the upper bound f(n)≤(n+1)(n−2)2f(n)\leq\frac{(n+1)(n-2)}{2}, while reported data suggest faster-than-linear growth; the asymptotic behavior remains unclear.

Current status (as of September 2026): The 2n−42n-4 universal conjecture is refuted by a published counterexample, but the exact maximum sort-number and its growth rate remain open.

Sources

Solutions 0

No solutions have been posted yet.