Valiant's conjecture that VBP differs from VNP

From papers

Let VBP\mathrm{VBP} be the class of polynomial families computable by polynomial-size algebraic branching programs, and let VNP\mathrm{VNP} be Valiant's class of polynomially verifiable families. The inclusions satisfy VBPVNP\mathrm{VBP}\subseteq\mathrm{VNP}. Valiant's conjecture. We have

VBPVNP.\mathrm{VBP}\neq\mathrm{VNP}.

This is a central separation question in algebraic complexity theory; the source gives no resolution.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Greta Panova, “Computational Complexity in Algebraic Combinatorics”, arXiv:2306.17511 (2023).

Additional references

2 papers in this index state this conjecture (2009–2023). The statement above is taken from the most recent of them; the others are arXiv:0910.2443.

Solutions 0

No solutions have been posted yet.