Generalised Sylvester's conjecture for two prime factors

Let 1\ell_1 and 2\ell_2 be distinct primes different from 33, and let nn be one of

n=12,n=122,n=1222.n=\ell_1\ell_2,\qquad n=\ell_1^2\ell_2,\qquad n=\ell_1^2\ell_2^2.

Generalised Sylvester's conjecture. If n≢±1(mod9)n\not\equiv\pm1\pmod9, then

rkE432n2(Q)={{0,2},122(mod3),1,122(mod3),{1,3},121(mod3).\operatorname{rk}E_{-432n^2}(\mathbb{Q})=\begin{cases}\{0,2\},&\ell_1\ell_2\equiv2\pmod3,\\1,&\ell_1\equiv\ell_2\equiv2\pmod3,\\\{1,3\},&\ell_1\equiv\ell_2\equiv1\pmod3.\end{cases}

If n±1(mod9)n\equiv\pm1\pmod9, then

rkE432n2(Q)={{1,3},122(mod3),{0,2},122(mod3),{0,2,4},121(mod3).\operatorname{rk}E_{-432n^2}(\mathbb{Q})=\begin{cases}\{1,3\},&\ell_1\ell_2\equiv2\pmod3,\\\{0,2\},&\ell_1\equiv\ell_2\equiv2\pmod3,\\\{0,2,4\},&\ell_1\equiv\ell_2\equiv1\pmod3.\end{cases}

This is the two-prime specialization of the generalized prediction. The paper proves the relevant Selmer parity and rank bounds, but the displayed exact rank alternatives depend on the stated Tate–Shafarevich parity assumption.

Sources & referencesView supporting material

Primary source

Dipramit Majumdar and Pratiksha Shingavekar, “Cube sum problem for integers having exactly two distinct prime factors”, arXiv:2211.17118 (2022).

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