Byott's conjecture on solubility of finite skew braces

Let $A$ be a finite skew brace with multiplicative group $(A,\cdot)$ and circle group $(A,\circ)$. Byott's conjecture. If $(A,\cdot)$ is soluble, then $(A,\circ)$ is soluble. The paper states that this conjecture is solved in the case of bi-skew braces; the general case is not resolved here.