Pate's conjecture on the largest eigenvalue of the complementary-permanent matrix

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Let AA be an n×nn\times n positive semi-definite Hermitian matrix, and let 1≤k<n1\leq k<n. For kk-element subsets I,J⊂[n]I,J\subset[n], define Ck(A)\mathscr{C}_k(A) by

(Ck(A))I,J=per⁡(A[I,J])per⁡(A[Ic,Jc]).(\mathscr{C}_k(A))_{I,J}=\operatorname{per}(A[I,J])\operatorname{per}(A[I^c,J^c]).

Pate's conjecture. The largest eigenvalue of Ck(A)\mathscr{C}_k(A) is per⁡(A)\operatorname{per}(A). This conjecture is refuted; the paper states that its k=1k=1 case has an 8×88\times8 counterexample and presents a new 5×55\times5 rank-22 counterexample.

References

Primary source

Tran Hoang Anh, “A simple counterexample for the permanent-on-top conjecture”, arXiv:2101.03428 (2022).

Additional references

2 papers in this index state this conjecture (2020–2021). The statement above is taken from the most recent of them; the others are arXiv:2002.04149.

Progress summary

Refreshed
Claimed solved

A paper reports that the conjecture is false, including a smaller five-by-five example, but this scan found no independent verification.

Pate’s conjecture asserts that the complementary-permanent matrix has largest eigenvalue equal to the permanent for every positive-semidefinite Hermitian input and every permitted kk. It is weaker than the permanent-on-top conjecture.

Known results

  • Pate proved the k=1k=1 case on a large subcone of Hermitian matrices and for all nonnegative real matrices.
  • Stephen W. Drury supplied an 8×88\times 8 counterexample for the k=1k=1 case.
  • Tran gave an explicit 5×55\times 5 counterexample, recorded in a 2022 survey.

2021 explicit counterexample

The paper A simple counterexample for the permanent-on-top conjecture presents a positive-semidefinite Hermitian matrix HH of size 5×55\times 5 and rank 22, with per⁡(H)=504\operatorname{per}(H)=504, for which the relevant eigenvalue exceeds the permanent; it states that the same construction refutes Pate’s conjecture for k=2k=2. The paper also records the earlier k=1k=1 counterexample.

Current status (as of September 2026): The conjecture is reported refuted by explicit counterexamples, including a 5×55\times 5 rank-22 example for k=2k=2; the reported refutation remains unverified by this review.

Sources

Solutions 0

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