SO-type super-A-polynomial branch conjecture

Let $K$ be a knot satisfying the exponential growth property. Let $\mathscr{A}^{\operatorname{SO}}(K;x,y,a,t)$ be the SO-type super-$A$-polynomial, and let $A^{\operatorname{SO}}(K;x,y,a)$ and $A^{\operatorname{SU}}(K;x,y,a)$ be the SO- and SU-type $a$-deformed $A$-polynomials.

SO-type super-A-polynomial branch conjecture. At $t=-1$, the zero locus

$$\mathscr{A}^{\operatorname{SO}}(K;x,y,a,t=-1)=0$$

includes the two branches

$$A^{\operatorname{SO}}(K;x,y,a)=0$$

and

$$A^{\operatorname{SU}}(K;x,y,a)=0.$$

The claim identifies both classical SO- and SU-type branches inside the decategorified SO-type super-$A$-polynomial; the supplied text does not give a resolution status.