Going-up spectrum realization conjecture for simultaneous Diophantine exponents

At least 5 years old · documented by

Let (λN)N≥1(\lambda_N)_{N\geq 1} and (λ^N)N≥1(\widehat{\lambda}_N)_{N\geq 1} be non-increasing sequences of real numbers. Assume that, for every N≥1N\geq 1, λ^N≥1/N\widehat{\lambda}_N\geq 1/N and

λ^N+λ^N2λN+⋯+λ^NNλNN−1≤1.\widehat{\lambda}_{N}+\frac{\widehat{\lambda}_{N}^{2}}{\lambda_{N}}+\cdots+\frac{\widehat{\lambda}_{N}^{N}}{\lambda_{N}^{N-1}}\leq 1.

Assume also that, for all k≥n≥1k\geq n\geq 1,

λk≥nλn+n−1n(k−1)(λn+1)+1,λ^k≥n+λ^n−2(n−1)(k−1).\lambda_{k}\geq\frac{n\lambda_{n}+n-1}{n(k-1)(\lambda_{n}+1)+1},\qquad \widehat{\lambda}_{k}\geq\frac{n+\widehat{\lambda}_{n}-2}{(n-1)(k-1)}.

Going-up spectrum realization conjecture. There is ξ‾∈RN\underline{\xi}\in\mathbb{R}^{\mathbb{N}} such that, for every N≥1N\geq 1, its first NN coordinates ξ‾N\underline{\xi}_N satisfy

λN(ξ‾N)=λNandλ^N(ξ‾N)=λ^N.\lambda_N(\underline{\xi}_N)=\lambda_N\quad\text{and}\quad\widehat{\lambda}_N(\underline{\xi}_N)=\widehat{\lambda}_N.

This conjecture asks whether the displayed necessary restrictions on the sequences are also sufficient for simultaneous realization by the projections of one infinite real vector. It is motivated by the preceding going-up inequalities and is presented as an expected sufficiency statement; no resolution is supplied here.

References

Primary source

Johannes Schleischitz, “Going-up theorems for simultaneous Diophantine approximation”, arXiv:2010.01000 (2021).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.