The all-charge multicenter Dirac lower-bound conjecture

Let M2M\geqslant2, let R1,,RMR3R_1,\ldots,R_M\in\mathbb{R}^3, and let νm0\nu_m\geqslant0 satisfy m=1Mνm1\sum_{m=1}^M\nu_m\leqslant1. Let D0D_0 be the free Dirac operator and let λ1\lambda_1 denote the first min-max level of the multicenter Dirac-Coulomb operator. The all-charge multicenter Dirac lower-bound conjecture. For every such choice of positions and charges,

λ1(D0m=1MνmxRm)λ1(D0m=1Mνmx)=1(m=1Mνm)2.\lambda_1\left(D_0-\sum_{m=1}^M\frac{\nu_m}{|x-R_m|}\right)\geqslant\lambda_1\left(D_0-\frac{\sum_{m=1}^M\nu_m}{|x|}\right)=\sqrt{1-\left(\sum_{m=1}^M\nu_m\right)^2}.

The inequality asserts that separating the nuclei cannot lower the first level below the merged point-charge value. The supplied status evidence says that this conjecture has been proved in the nonrelativistic case; the relativistic assertion is presented here as a conjecture.

Sources & referencesView supporting material

Primary source

Maria J. Esteban, Mathieu Lewin and Éric Séré, “Dirac-Coulomb operators with general charge distribution. I. Distinguished extension and min-max formulas”, arXiv:2003.04004 (2021).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.