Conjecture on adjacent factorizations in generalized arithmetic monoids with gcd one

Let MM be the generalized arithmetic monoid under consideration, let mMm\in M, and let Z(m)\mathcal Z(m) be its set of factorizations. For factorizations z,zZ(m)z,z'\in\mathcal Z(m), write z|z| for their lengths and d(z,z)d(z,z') for their distance. Let aa be the parameter appearing in the source formulas. The adjacent-factorization conjecture. Assume

gcd(h1,d)=1\gcd(h-1,d)=1

and that there exist z,zZ(m)z,z'\in\mathcal Z(m) such that zzz\ne z', z=z|z|=|z'|, and z1>z1z_1>z'_1. Then there exists fZ(m)f\in\mathcal Z(m) such that

f=z+1,d(f,z)d(z,z),d(f,z)d(z,z).|f|=|z|+1,\qquad d(f,z)\leq d(z,z'),\qquad d(f,z')\leq d(z,z').

Further, if hdh\leq d, then

f=(z1+a2,z2aah+da2(ah+da)dah+da,z3ah+da2(ah+da)d),f=\left(z_1+\left\lceil\frac a2\right\rceil,z_2-\frac{a-\frac{ah+d-\left\lceil\frac a2\right\rceil(ah+d-a)}d}{ah+d-a},z_3-\frac{ah+d-\left\lceil\frac a2\right\rceil(ah+d-a)}d\right),

and if h>dh>d, then

f=(z1+a2,z2aah+da2(ah+da)dah+da,Az3ah+da2(ah+da)d).f=\left(z_1+\left\lfloor\frac a2\right\rfloor,z_2-\frac{a-\frac{ah+d-\left\lfloor\frac a2\right\rfloor(ah+d-a)}d}{ah+d-a},A z_3-\frac{ah+d-\left\lfloor\frac a2\right\rfloor(ah+d-a)}d\right).

The claim is intended to establish the length-adjacent factorization condition needed for strict inequality between regular and monotone catenary degrees in the gcd-one case; the source provides no resolution, so it remains open.

Sources & referencesView supporting material

Primary source

Daniel Gonzalez Cedre, Cameron Wright and Jenna Zomback, “Monotone Catenary Degree in Numerical Monoids”, arXiv:1912.08114 (2022).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.