Baker's conjecture on concordance of tight fibered knots

Let K0K_{0} and K1K_{1} be fibered knots in S3S^{3} supporting the tight contact structure. Baker's conjecture. If K0K_{0} and K1K_{1} are concordant, then K0=K1K_{0}=K_{1}. The conjecture predicts that tight, fibered knots are unique in their concordance classes. Its status is not resolved in the supplied text.

Sources & referencesView supporting material

Primary source

Dongtai He, Diana Hubbard and Linh Truong, “On the Upsilon invariant of fibered knots and right-veering open books”, arXiv:1911.05776 (2019).

Additional references

3 papers in this index state this conjecture (2014–2019). The statement above is taken from the most recent of them; the others are arXiv:1502.01102, arXiv:1409.7646.

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