Baker's conjecture on concordance of tight fibered knots

About 12 years old · traced to

Let K0K_{0} and K1K_{1} be fibered knots in S3S^{3} supporting the tight contact structure. Baker's conjecture. If K0K_{0} and K1K_{1} are concordant, then K0=K1K_{0}=K_{1}. The conjecture predicts that tight, fibered knots are unique in their concordance classes. Its status is not resolved in the supplied text.

References

Primary source

Dongtai He, Diana Hubbard and Linh Truong, “On the Upsilon invariant of fibered knots and right-veering open books”, arXiv:1911.05776 (2019).

Additional references

3 papers in this index state this conjecture (2014–2019). The statement above is taken from the most recent of them; the others are arXiv:1502.01102, arXiv:1409.7646.

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.