Guo–Zudilin q-analogue with half truncation

Let $(a;q)_k=\prod_{j=0}^{k-1}(1-aq^j)$ be the $q$-shifted factorial, let $\Phi_n(q)$ be the $n$th cyclotomic polynomial, and let $n>1$ be odd and $r\geqslant 1$. Guo–Zudilin's half-truncation q-conjecture. Modulo $\Phi_n(q)^3$,

$$\sum_{k=0}^{(n^{r+1}-1)/2}\frac{(q;q^2)_k^4}{(q^2;q^2)_k^4}q^{2k} \equiv \left(\sum_{k=0}^{(n-1)/2}\frac{(q;q^2)_k^4}{(q^2;q^2)_k^4}q^{2k}\right) \left(\sum_{k=0}^{(n^r-1)/2}\frac{(q^{n^2};q^{2n^2})_k^4}{(q^{2n^2};q^{2n^2})_k^4}q^{2n^2k}\right).$$

This is the natural half-truncated $q$-analogue of the corresponding equivalent classical supercongruence. The source explicitly notes that this conjecture is not equivalent to the full-truncation $q$-conjecture, and gives no resolution.