Lemke Oliver–Soundararajan conjecture for consecutive prime residue patterns

Let q3q\ge3 be a positive integer, let aa and bb be reduced residue classes modulo qq, and set hba(modq)h\equiv b-a\pmod q. Define

α(y)=1qφ(q)logy,ϵq(a,b)=#{0<t<h:(t+a,q)=1}φ(q)qh.\alpha(y)=1-\frac{q}{\varphi(q)\log y},\qquad \epsilon_q(a,b)=\#\{0<t<h:(t+a,q)=1\}-\frac{\varphi(q)}{q}h.

Let Sq,0\mathfrak{S}_{q,0} denote the inclusion–exclusion modification of the modified singular series introduced in the preceding context, and define D(a,b;y)\mathcal{D}(a,b;y) by the sum in the statement below. Lemke Oliver–Soundararajan conjecture. The consecutive-prime counting function satisfies

π(x;q,(a,b))1q2xα(y)ϵq(a,b)(qφ(q)α(y)logy)2D(a,b;y)dy,\pi(x;q,(a,b))\sim\frac1q\int_2^x\alpha(y)^{\epsilon_q(a,b)}\left(\frac{q}{\varphi(q)\alpha(y)\log y}\right)^2\mathcal{D}(a,b;y)\,dy,

where

D(a,b;y)=h>0\hba(modq)A{0,h}T[1,h1](t+a,q)=1 tT(1)TSq,0(AT)(qφ(q)α(y)logy)Tα(y)hφ(q)/q.\mathcal{D}(a,b;y)=\sum_{\substack{h>0\h\equiv b-a\pmod q}}\sum_{\mathcal{A}\subset\{0,h\}}\sum_{\substack{\mathcal{T}\subset[1,h-1]\\(t+a,q)=1\ \forall t\in\mathcal{T}}}(-1)^{|\mathcal{T}|}\mathfrak{S}_{q,0}(\mathcal{A}\cup\mathcal{T})\left(\frac{q}{\varphi(q)\alpha(y)\log y}\right)^{|\mathcal{T}|}\alpha(y)^{h\varphi(q)/q}.

This conjecture is intended to explain the observed biases among consecutive prime residue patterns modulo qq, while incorporating lower-order terms omitted in the original heuristic. The source attributes it to Lemke Oliver and Soundararajan and does not provide evidence of resolution.

Sources & referencesView supporting material

Primary source

David Wu, “Nonuniform Distributions of Residues of Prime Sequences in Prime Moduli”, arXiv:1908.07095 (2019).

Additional references

3 papers in this index state this conjecture (2018–2019). The statement above is taken from the most recent of them; the others are arXiv:1809.06158, arXiv:1803.10223.

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.