Modified André–Pink–Zannier conjecture over a curve

Let KK be a field of characteristic 00, let SS be a base curve, and let π ⁣:AS\pi\colon \mathcal{A}\to S be an abelian scheme that is not isotrivial. Let AΓ\mathcal{A}_{\Gamma} denote the specified isogeny orbit, let VA\mathcal{V}\subset \mathcal{A} be an irreducible subvariety, and let As\mathcal{A}_s and Aξ\mathcal{A}_\xi denote the fiber over sSs\in S and the geometric generic fiber, respectively. Write (Aξ)tors(\mathcal{A}_\xi)_{\operatorname{tors}} for the torsion subgroup and Tr(AξK(S)/Kˉ(Kˉ))\operatorname{Tr}(\mathcal{A}_\xi^{\overline{K(S)}/\bar{K}}(\bar{K})) for the relevant K(S)/Kˉ\overline{K(S)}/\bar{K}-trace.

Modified André–Pink–Zannier conjecture. If AΓV\mathcal{A}_{\Gamma}\cap\mathcal{V} is Zariski dense in V\mathcal{V}, then one of the following holds:

  1. V\mathcal{V} is a translate of an abelian subvariety of As\mathcal{A}_s by a point of AΓAs\mathcal{A}_{\Gamma}\cap\mathcal{A}_s for some sSs\in S.
  2. π(V)=S\pi(\mathcal{V})=S and, over K(S)\overline{K(S)}, every irreducible component of Vξ\mathcal{V}_\xi is a translate of an abelian subvariety of Aξ\mathcal{A}_\xi by a point in
(Aξ)tors+Tr(AξK(S)/Kˉ(Kˉ)).(\mathcal{A}_\xi)_{\operatorname{tors}}+\operatorname{Tr}\left(\mathcal{A}_\xi^{\overline{K(S)}/\bar{K}}(\bar{K})\right).

This is a modified version of the André–Pink–Zannier conjecture for a base curve and generalizes the setting of the theorem proved in the paper. The conjecture allows arbitrary characteristic-zero KK, with no restrictions on the abelian scheme or the fixed abelian variety; the paper notes that the required intersection bound is not known in full generality.

Sources & referencesView supporting material

Primary source

Gabriel Andreas Dill, “Unlikely intersections with isogeny orbits in a product of elliptic schemes”, arXiv:1902.01323 (2019).

Additional references

2 papers in this index state this conjecture (2018–2019). The statement above is taken from the most recent of them; the others are arXiv:1801.05701.

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.