Improved remainder estimate under strong convexity

About 8 years old · traced to

Let A0A^0 be a scalar operator and let

Σλ0={ξ ⁣:A0(ξ)=λ}\Sigma^0_\lambda=\{\xi\colon A^0(\xi)=\lambda\}

be a strongly convex surface, meaning that

±∑j,kAξjξk0(ξ)ηjηk≥ϵ∣η∣2\pm\sum_{j,k}A^0_{\xi_j\xi_k}(\xi)\eta_j\eta_k\geq\epsilon|\eta|^2

for all ξ∈Σλ0\xi\in\Sigma^0_\lambda and all η\eta satisfying

∑jAξj0(ξ)ηj=0,\sum_jA^0_{\xi_j}(\xi)\eta_j=0,

where the sign depends on the connected component of Σλ\Sigma_\lambda containing ξ\xi. Improved remainder estimate. Under this additional assumption, the last term in the right-hand side of the estimate in Theorem 2.8 should be replaceable by

Cshs(∣x∣+1)k−d.C_s h^s(|x|+1)^{k-d}.

The proposed improvement would make the remainder decay in xx rather than grow as (∣x∣+1)k(|x|+1)^k; the source presents it as a hoped-for consequence of strong convexity, and no resolution is supplied.

References

Primary source

Victor Ivrii, “Complete Differentiable Semiclassical Spectral Asymptotics”, arXiv:1809.07126 (2018).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.