Uniform-distribution conjecture for the random variable X_l(m,N)

From papers

Let N3N\ge 3, and let ll and mm be positive integers such that 1lN1\le l\le N, 2mN12\le m\le N-1, and both ll and mm are relatively prime to NN. Let Xl(m,N)X_l(m,N) be the random variable from Definition 1.21.2. Uniform-distribution conjecture. The random variable Xl(m,N)X_l(m,N) is uniformly distributed if and only if NN is a prime number. The conjecture is motivated by computations and heuristic arguments: the prime case is established in the preceding discussion, while examples for small composite values of NN suggest that primality is also necessary.

Progress summary

Open

The conjecture has a verified prime case, but no public proof or counterexample for the composite case was found.

The conjecture asserts that the random variable is uniformly distributed exactly when NN is prime. It appears in a 20182018 paper on discrete random variables; the prime case is established there, while the converse remains conjectural.

Current status (as of August 2026): Uniformity for prime NN is settled, but the claimed necessity of primality for composite NN remains open, with no verified progress located.

Sources
Sources & referencesView supporting material

Primary source

Romeo Meštrović, “On some discrete random variables arising from recent study on statistical analysis of compressive sensing”, arXiv:1803.02260 (2018).

Solutions 1

Counterexample

In fact, for every odd integer N3N\ge3 and every \ell coprime to NN, the random variable X(2,N)X_\ell(2,N) is uniformly distributed, regardless of whether NN is prime.

Put

ζ=exp(2πiN).\zeta=\exp\left(-\frac{2\pi i\ell}{N}\right).

Since gcd(,N)=1\gcd(\ell,N)=1, its powers are precisely the NN distinct NN-th roots of unity. The variable X(2,N)X_\ell(2,N) chooses one of the

(N2)\binom N2

unordered pairs of distinct roots with equal probability.

No such pair has sum zero: otherwise its elements would be antipodal, which is impossible when NN is odd. Now let z,wz,w be any two unit-modulus roots with

s=z+w0.s=z+w\ne0.

Because z=1/z\overline z=1/z and w=1/w\overline w=1/w,

s=1z+1w=szw.\overline s = \frac1z+\frac1w = \frac{s}{zw}.

Consequently,

zw=ss.zw=\frac{s}{\overline s}.

Thus the unordered pair {z,w}\{z,w\} is uniquely determined by its sum: its members are exactly the two roots of

T2sT+ss=0.T^2-sT+\frac{s}{\overline s}=0.

Therefore all (N2)\binom N2 pair sums are distinct, and each occurs with probability

1(N2).\frac1{\binom N2}.

Taking

N=9,=1,m=2N=9,\qquad \ell=1,\qquad m=2

gives 3636 equally probable values although NN is composite. All stated hypotheses hold:

2mN1,gcd(,N)=gcd(m,N)=1.2\le m\le N-1,\qquad \gcd(\ell,N)=\gcd(m,N)=1.

More generally, every odd composite NN provides a counterexample.

The source's Proposition 2.1 already establishes uniformity at the allowed endpoint m=N1m=N-1 for every NN. The interior family m=2m=2 above shows that excluding this endpoint would still not repair the conjecture.

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Shivam Patel ·