Tohăneanu's low-exponent supersolvability conjecture for free arrangements

Let APk1\mathcal{A}\subset\mathbb P^{k-1} be a free hyperplane arrangement with exponents

exp(A)=(1,2,,2k2,3).\operatorname{exp}(\mathcal{A})=(1,\underbrace{2,\ldots,2}_{k-2},3).

Tohăneanu's low-exponent supersolvability conjecture. Then A\mathcal{A} is supersolvable. The conjecture concerns free arrangements with exactly one exponent equal to 33 and is verified in ranks 44 and 55, as well as for inductively free arrangements of arbitrary rank; the general case remains open.

Sources & referencesView supporting material

Primary source

Stefan O. Tohaneanu, “Free arrangements with low exponents”, arXiv:1707.07091 (2022).

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