Equality of two quadrant marked mesh pattern polynomials

Let $Q_{132}^{(a,b,\tau,c)}(t,x)$ denote the polynomial associated with 132-avoiding permutations and the indicated quadrant marked mesh pattern parameters. The parameters are $(0,k,\emptyset,0)$ and $(1,k-1,\emptyset,0)$, with $k\geq 1$.

Equality conjecture. For all $k\geq 1$, we have

$$Q_{132}^{(0,k,\emptyset,0)}(t,x)=Q_{132}^{(1,k-1,\emptyset,0)}(t,x).$$

The equality is motivated by the observed coincidence of the corresponding polynomials. Its resolution is not specified in the supplied text.