Algebraic-solution relation for q-deformed conformal blocks

Let T(u,s;qZ)\mathcal{T}(u,s;q|Z) be any uu-inverse invariant tau function, and let C(u;qZ)C(u;q|Z) be its coefficient function. Here uu-inverse invariance means invariance under uu1u\mapsto u^{-1}, and Pn(q)P_n(q) is defined by

Pn(q)=ϵ=±1(q12ϵq;q,q)ϵ=±1((q2n+1/2)ϵq;q,q).P_n(q)=\frac{\prod\limits_{\epsilon=\pm1}(q^{\frac12\epsilon}q;q,q)_\infty}{\prod\limits_{\epsilon=\pm1}((q^{2n+1/2})^\epsilon q;q,q)_\infty}.

For n>0n>0, set k=2nk=2n, and for n<0n<0, set k=2n1k=-2n-1.

Algebraic-solution relation. For s=±1s=\pm1,

T(q1/2,±1;qZ)=C(q1/2;qZ)(q3/2;q,q)(q1/2;q,q)(Z1/2q1/2;q1/2,q1/2).\mathcal{T}(q^{1/2},\pm1;q|Z)=\frac{C(q^{1/2};q|Z)}{(q^{3/2};q,q)_\infty(q^{1/2};q,q)_\infty}(\mp Z^{1/2}q^{1/2};q^{1/2},q^{1/2})_\infty.

Equivalently,

(Z1/2q1/2;q1/2,q1/2)=nZ(1)nZn2+n/2Pn(q)F(q2n+1/2,q,qZ),(\mp Z^{1/2}q^{1/2};q^{1/2},q^{1/2})_\infty=\sum_{n\in\mathbb{Z}}(\mp1)^nZ^{n^2+n/2}P_n(q)\mathcal{F}(q^{2n+1/2},q,q|Z),

where

Pn(q)=j=0k11((1qj+1/2)(1qj1/2))kj.P_n(q)=\prod_{j=0}^{k-1}\frac{1}{\left((1-q^{j+1/2})(1-q^{-j-1/2})\right)^{k-j}}.

This relation gives the special algebraic, Bäcklund-invariant solutions associated with u=q1/2u=q^{1/2} and s=±1s=\pm1; the supplied text gives no separate resolution status.

Sources & referencesView supporting material

Primary source

M. A. Bershtein and A. I. Shchechkin, “Q-deformed Painleve tau function and q-deformed conformal blocks”, arXiv:1608.02566 (2019).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.