Equality of the absolute Galois group with the dessin automorphism subgroup

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Let L\mathcal{L} be the lattice of biased dessins, let Γ′=Aut⁡(L)\Gamma' = \operatorname{Aut}(\mathcal{L}), and let Γ0′\Gamma'_0 be the subgroup of Γ′\Gamma' that fixes the three vertices of the bottom element D1D_1. The absolute Galois group Γ\Gamma is a subgroup of Γ0′\Gamma'_0. Equality conjecture.

Γ=Γ0′.\Gamma = \Gamma'_0.

The preceding theorem establishes the inclusion, while the source states that there is currently no evidence or proof strategy for the reverse inclusion.

References

Primary source

Jonathan Fine, “Bias and dessins”, arXiv:1506.06389 (2018).

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