The rationalized Farrell-Jones conjecture

From papers

Let GG be a group and nZn\in\mathbb{Z}. The rationalized Farrell-Jones assembly map is

(C)(FCyc) s+t=n\s0,t1Hs(BZGC;Q)Q[WGC]ΘC(Kt(Z[C])ZQ)Kn(Z[G])ZQ,\bigoplus_{(C)\in(\mathcal{FCyc})}\ \bigoplus_{\substack{s+t=n\s\geq0,\,t\geq-1}} H_s(BZ_GC;\mathbb{Q})\otimes_{\mathbb{Q}[W_GC]}\Theta_C\bigl(K_t(\mathbb{Z}[C])\otimes_{\mathbb{Z}}\mathbb{Q}\bigr)\longrightarrow K_n(\mathbb{Z}[G])\otimes_{\mathbb{Z}}\mathbb{Q},

where (C)(C) ranges over conjugacy classes of finite cyclic subgroups, ZGCZ_GC is the centralizer, WGCW_GC is the Weyl group, and ΘC\Theta_C is the specified idempotent endomorphism.

Rationalized Farrell-Jones conjecture. For every group GG and every nZn\in\mathbb{Z}, this rationalized Farrell-Jones assembly map is an isomorphism.

This is the rationalized version of the Farrell-Jones conjecture and extends Hsiang's conjecture from torsion-free groups to arbitrary groups.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Wolfgang Lueck, Holger Reich, John Rognes and Marco Varisco, “Algebraic K-theory of group rings and the cyclotomic trace map”, arXiv:1504.03674 (2016).

Additional references

2 papers in this index state this conjecture (2014–2015). The statement above is taken from the most recent of them; the others are arXiv:1401.0357.

Solutions 0

No solutions have been posted yet.