A squared Pólya–Szegö and Diaz–Metcalf inequality for positive linear maps

From papers

Let Φ\Phi be a unital positive linear map, and let AA and BB be positive operators satisfying

0<m12AM12,0<m_{1}^{2}\leq A\leq M_{1}^{2},

and

0<m22BM22,0<m_{2}^{2}\leq B\leq M_{2}^{2},

for positive real numbers m1M1m_{1}\leq M_{1} and m2M2m_{2}\leq M_{2}. Write ABA\sharp B for the operator geometric mean. Squared Pólya–Szegö and Diaz–Metcalf inequalities. The inequalities

(Φ(A)Φ(B))214(M1M2m1m2+m1m2M1M2)2Φ(AB)2(\Phi(A)\sharp\Phi(B))^2\leq\frac{1}{4}\left(\sqrt{\frac{M_1M_2}{m_1m_2}}+\sqrt{\frac{m_1m_2}{M_1M_2}}\right)^2\Phi(A\sharp B)^2

and

(M2m2M1m1Φ(A)+Φ(B))2(M2m1+m2M1)2Φ(AB)2\left(\frac{M_2m_2}{M_1m_1}\Phi(A)+\Phi(B)\right)^2\leq\left(\frac{M_2}{m_1}+\frac{m_2}{M_1}\right)^2\Phi(A\sharp B)^2

should hold. These inequalities refine operator versions of the Pólya–Szegö and Diaz–Metcalf inequalities by relating the geometric mean of the images, and a weighted sum of the images, to the image of the geometric mean. The supplied text does not give resolution evidence beyond presenting the result as a conjecture, so its status is left open.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Mohammad Sal Moslehian and Xiaohui Fu, “Squaring operator Pólya–Szegö and Diaz–Metcalf type inequalities”, arXiv:1501.02939 (2015).

Solutions 0

No solutions have been posted yet.