Power-improved two-weight Bergman inequality

About 12 years old · traced to

Let p>1p>1, and let μ1\mu_1 and μ2\mu_2 be weights on the upper half-plane R+2\mathbb{R}_{+}^2. For some r>1r>1, consider the pair of powered weights (μ1r,μ2r)(\mu_1^r,\mu_2^r) in the two-weight class Ap+(R+2)A_p^+(\mathbb{R}_{+}^2), and use the associated inequality

∫R+2∣∫R+2−f(w)(z−w‾)2 dA(w)∣pμ1(z) dA(z)≤C∫R+2∣f(z)∣pμ2(z) dA(z).\int_{\mathbb{R}_{+}^2}\left|\int_{\mathbb{R}_{+}^2}-\frac{f(w)}{(z-\overline{w})^2}\,dA(w)\right|^p\mu_1(z)\,dA(z)\le C\int_{\mathbb{R}_{+}^2}|f(z)|^p\mu_2(z)\,dA(z).

Power-improved two-weight conjecture. If (μ1r,μ2r)∈Ap+(R+2)(\mu_1^r,\mu_2^r)\in A_p^+(\mathbb{R}_{+}^2) for some r>1r>1, then the displayed inequality holds for some C>0C>0. This is presented as a variant motivated by a cited result, but the supplied source material gives no resolution; the conjecture therefore remains open.

References

Primary source

Liwei Chen, “Weighted Bergman Projection on the Hartogs Triangle”, arXiv:1410.6205 (2015).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.