The Stokes triangulation–seed correspondence conjecture

About 12 years old · traced to

Let TT be a labeled Stokes triangulation of an orbifold (O,A)(\mathbf{O},\mathbf{A}). Consider a sequence of signed flips

T′=μkN(εN)∘⋯∘μk1(ε1)(T).T'=\mu_{k_N}^{(\varepsilon_N)}\circ\cdots\circ\mu_{k_1}^{(\varepsilon_1)}(T).

Let (B,x,y)(B,x,y) be a seed with B=B(T)B=B(T), and apply the same sequence of signed mutations:

(B′,x′,y′)=μkN(εN)∘⋯∘μk1(ε1)(B,x,y).(B',x',y')=\mu_{k_N}^{(\varepsilon_N)}\circ\cdots\circ\mu_{k_1}^{(\varepsilon_1)}(B,x,y).

Stokes triangulation–seed correspondence conjecture. We have T=T′T=T' if and only if (B′,x′,y′)=(B,x,y)(B',x',y')=(B,x,y). This conjecture asserts that the seed obtained from signed mutations records exactly whether the corresponding sequence of signed flips returns the Stokes triangulation to its initial state.

References

Primary source

Kohei Iwaki and Tomoki Nakanishi, “Exact WKB analysis and cluster algebras II: Simple poles, orbifold points, and generalized cluster algebras”, arXiv:1409.4641 (2014).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.