Abhyankar's conjecture for affine curves

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Let kk be an algebraically closed field of characteristic p>0p>0. Let XX be a smooth projective curve of genus gg over kk, let BB be a non-empty set of rr points of XX, and let U=X−BU=X-B. For a finite group GG, let p(G)p(G) denote the subgroup generated by the pp-subgroups of GG. Abhyankar's conjecture for affine curves. The group GG is the Galois group of an unramified cover of UU if and only if G/p(G)G/p(G) has a generating set of size at most 2g+r−12g+r-1. This conjecture is presented in the paper as proved by Serre, Raynaud, and Harbater, so its status is solved.

References

Primary source

David Harbater, Andrew Obus, Rachel Pries and Katherine Stevenson, “Abhyankar's conjectures in Galois theory: Current status and future directions”, arXiv:1408.0859 (2017).

Progress summary

Refreshed
Claimed solved

The conjecture is regarded as settled: the allowed finite groups were characterized through work by Serre, Raynaud, and Harbater in the 1990s.

Abhyankar posed the conjecture in 1957. It characterizes exactly which finite groups occur as Galois groups of unramified covers of an affine curve, using the genus, the number of deleted points, and the group's contribution from characteristic-pp subgroups.

Known results

  • Serre, 1990: solved the soluble-group case for the affine line.
  • Raynaud, 1994: proved the affine-line case in full.
  • Harbater, 1994: extended the result to arbitrary smooth affine curves using formal patching.
  • The necessary direction follows from Grothendieck's tame fundamental-group result.

1994 resolution

The cited literature reports that Raynaud and Harbater proved the stated criterion, with stronger versions controlling ramification at a selected boundary point. Later expositions from 2017--2020 continue to describe the conjecture as affirmatively solved; the earlier 2014 source's contrary “open” label is superseded.

Current status (as of September 2026): the conjecture is reported as proved for all affine curves, with no remaining open case identified in the supplied sources.

Sources

Solutions 0

No solutions have been posted yet.