Milnor–Tjurina conjecture for non-complete-intersection surface singularities in C4

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Let (V,0)(V,0) be a normal surface singularity in C4\mathbb C^4 that is not a complete intersection. Milnor–Tjurina conjecture in C4.

μ≥τ−1,\mu\geq \tau-1,

with equality if and only if (V,0)(V,0) is quasi-homogeneous. The claim concerns the non-Gorenstein determinantal case, where the semi-universal deformation has smooth base and α=0\alpha=0. The source presents it as an open conjecture following discussion of the difficulty of computing the Milnor number.

References

Primary source

Jonathan Wahl, “Milnor and Tjurina numbers for smoothings of surface singularities”, arXiv:1307.6491 (2016).

Progress summary

Refreshed
Claimed progress

A 2016 paper gives an explicit counterexample to the equality characterization, while the inequality itself remains unproved.

The conjecture concerns normal, non-complete-intersection surface singularities in C4\mathbb{C}^4: it asserts μ≥τ−1\mu\geq\tau-1, with equality exactly in the quasi-homogeneous case. A 2013 source presented the statement as unresolved in the non-Gorenstein determinantal setting.

2016 counterexample to the equality characterization

In On discriminants, Tjurina modifications and the geometry of determinantal singularities, a family defined by maximal minors is computed to satisfy μ=k+ℓ+1\mu=k+\ell+1 and τ=k+ℓ+2\tau=k+\ell+2, hence μ=τ−1\mu=\tau-1, although the singularities are not quasi-homogeneous. This refutes the “if and only if” clause if the calculations are accepted; the paper does not disprove μ≥τ−1\mu\geq\tau-1.

Community submission (unverified)

The September 5, 2026 submission reproduces this family and argues, via its Tjurina transform and incompatible weight requirements, that it is a non-quasi-homogeneous counterexample with μ=τ−1\mu=\tau-1. This submission is unverified, though the same claimed construction appears in the 2016 paper.

Current status (as of September 2026): The equality characterization has a published but unverified counterexample; the inequality μ≥τ−1\mu\geq\tau-1 remains open.

Sources

Solutions 1

CounterexampleWe analyze the Milnor–Tjurina conjecture μ≥τ−1\mu\ge\tau-1 for non-complete-intersection normal surface singularities in C4\mathbb C^4. The key unresolved point is the equality case μ=τ−1\mu=\tau-1. A previously claimed non-quasi-homogeneous counterexample was later found to be incorrect, so it does not disprove the conjecture. Thus both the general inequality and the characterization of equality remain open. GPT 5.6 usedSee full solutionHide full solution

Published counterexample to the equality characterization

The conjecture as stated is false: equality μ=τ−1\mu=\tau-1 does not imply quasi-homogeneity. The following family of counterexamples was constructed by Anne Frühbis-Krüger.

For integers k,ℓ≥3k,\ell\geq 3, let (Xk,ℓ,0)⊂(C4,0)(X_{k,\ell},0)\subset(\mathbb C^4,0) be defined by the maximal minors of

Ak,ℓ=(z+xyxk+w2wℓzy).A_{k,\ell}= \begin{pmatrix} z+x & y & x^k+w^2\\ w^\ell & z & y \end{pmatrix}.

This is an isolated Cohen–Macaulay codimension-two surface singularity of type (2,3,2)(2,3,2). In particular it is a normal surface germ. Its determinantal ideal has height two and three minimal generators, so it is not a complete intersection.

Let Yk,ℓY_{k,\ell} be its Tjurina transform. It has precisely two isolated singularities:

(Yk,ℓ,p0)≅Aℓ−1,(Yk,ℓ,p∞)≅Dk+1.(Y_{k,\ell},p_0)\cong A_{\ell-1}, \qquad (Y_{k,\ell},p_\infty)\cong D_{k+1}.

Both are quasi-homogeneous. Consequently,

∑p∈Sing⁡(Yk,ℓ)μ(Yk,ℓ,p)=(ℓ−1)+(k+1)=k+ℓ.\sum_{p\in\operatorname{Sing}(Y_{k,\ell})}\mu(Y_{k,\ell},p) =(\ell-1)+(k+1)=k+\ell.

For an isolated determinantal surface of type (2,3,2)(2,3,2), the topology of the Tjurina transform gives

μ(Xk,ℓ)=1+∑p∈Sing⁡(Yk,ℓ)μ(Yk,ℓ,p),\mu(X_{k,\ell}) = 1+\sum_{p\in\operatorname{Sing}(Y_{k,\ell})} \mu(Y_{k,\ell},p),

and hence

μ(Xk,ℓ)=k+ℓ+1.\mu(X_{k,\ell})=k+\ell+1.

On the deformation-theoretic side,

τ(Xk,ℓ)=h1(Yk,ℓ,TYk,ℓ)+∑p∈Sing⁡(Yk,ℓ)τ(Yk,ℓ,p).\tau(X_{k,\ell}) = h^1(Y_{k,\ell},T_{Y_{k,\ell}}) + \sum_{p\in\operatorname{Sing}(Y_{k,\ell})} \tau(Y_{k,\ell},p).

For this family, the direct T1T^1-calculation gives

h1(Yk,ℓ,TYk,ℓ)=2h^1(Y_{k,\ell},T_{Y_{k,\ell}})=2

and therefore

τ(Xk,ℓ)=2+(ℓ−1)+(k+1)=k+ℓ+2.\tau(X_{k,\ell}) = 2+(\ell-1)+(k+1) = k+\ell+2.

Thus

μ(Xk,ℓ)=τ(Xk,ℓ)−1.\boxed{\mu(X_{k,\ell})=\tau(X_{k,\ell})-1}.

Nevertheless, Xk,ℓX_{k,\ell} is not quasi-homogeneous. One way to see the incompatibility is to compare the two hyperplane sections used in the cited construction. The section w=0w=0 requires weights proportional to

(wt⁡x,wt⁡y,wt⁡z)=(2,k+1,2),(\operatorname{wt}x,\operatorname{wt}y,\operatorname{wt}z) =(2,k+1,2),

whereas the section x=0x=0 requires

(wt⁡y,wt⁡z,wt⁡w)=(ℓ+4,2ℓ+2,3).(\operatorname{wt}y,\operatorname{wt}z,\operatorname{wt}w) =(\ell+4,2\ell+2,3).

In particular, a common grading would require simultaneously

wt⁡ywt⁡z=k+12andwt⁡ywt⁡z=ℓ+42ℓ+2,\frac{\operatorname{wt}y}{\operatorname{wt}z} = \frac{k+1}{2} \qquad\text{and}\qquad \frac{\operatorname{wt}y}{\operatorname{wt}z} = \frac{\ell+4}{2\ell+2},

which is impossible for k,ℓ≥3k,\ell\geq3.

For the smallest example k=ℓ=3k=\ell=3,

A3,3=(z+xyx3+w2w3zy),μ(X3,3)=7,τ(X3,3)=8,A_{3,3}= \begin{pmatrix} z+x & y & x^3+w^2\\ w^3 & z & y \end{pmatrix}, \qquad \mu(X_{3,3})=7,\quad \tau(X_{3,3})=8,

while X3,3X_{3,3} is not quasi-homogeneous.

Therefore the “equality if and only if quasi-homogeneous” clause of the conjecture is disproved. This family does not refute the remaining inequality μ≥τ−1\mu\geq\tau-1.

Reference. A. Frühbis-Krüger, “On discriminants, Tjurina modifications and the geometry of determinantal singularities,” Topology and its Applications 234 (2018), 375–396, Section 4, especially pp. 21–23; arXiv:1611.02625.