Rational Catalan q,t-symmetry refinement

Let Ym/nY_{m/n} be the set of m/nm/n Dyck paths, let h+(D)h_{+}(D) be the stated statistic, and define

Cn,m(q,t)=DYm/nqδm,nDth+(D),δm,n=(m1)(n1)2.C_{n,m}(q,t)=\sum_{D\in Y_{m/n}}q^{\delta_{m,n}-|D|}t^{h_{+}(D)},\qquad \delta_{m,n}=\frac{(m-1)(n-1)}{2}.

Let P~n,m\widetilde{P}_{n,m} be the transformed DAHA element, let hnh_n be the complete symmetric function, and let cn,m(λ)c_{n,m}(\lambda) and gλg_\lambda be the coefficients defined in the source. Rational Catalan q,t-symmetry conjecture.

Cn,m(q,t)=(hnP~n,m1)=λncn,m(λ)gλ.C_{n,m}(q,t)=(h_n\mid\widetilde{P}_{n,m}\mid1)=\sum_{\lambda\vdash n}\frac{c_{n,m}(\lambda)}{g_\lambda}.

Since the right-hand side is symmetric in qq and tt, this would imply Cn,m(q,t)=Cn,m(t,q)C_{n,m}(q,t)=C_{n,m}(t,q); the source notes that the claim is known for m=n+1m=n+1 and otherwise leaves it conjectural.

Sources & referencesView supporting material

Primary source

Eugene Gorsky and Andrei Neguţ, “Refined knot invariants and Hilbert schemes”, arXiv:1304.3328 (2015).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.