The top-twisted equality conjecture for Jack characters
The top-twisted equality conjecture for Jack characters
Let be a partition, let be a Young diagram, and let . Denote by the Jack character and by the orientability generating series. The top-twisted equality conjecture. The top-twisted parts of these two quantities are equal:
This is presented as a conjectural consequence concerning the highest-degree, or top-twisted, contributions of the Jack character and its orientability generating series; the source gives no resolution beyond the stated assertion.
Sources & referencesView supporting material
Primary source
Maciej Dołęga, Valentin Féray and Piotr Śniady, “Jack polynomials and orientability generating series of maps”, arXiv:1301.6531 (2014).
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
Sign in to submit a solution.
No solutions have been posted yet.