Cocircuit-rank conjecture for non-graphic binary matroids

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Let MM be a 33-connected non-graphic binary matroid. Define Y(M)Y(M) to be the set of elements of MM avoiding more than r∗(M)−1r^*(M)-1 non-separating cocircuits, and let Y~(M):=E(M)−Y(M)\widetilde{Y}(M):=E(M)-Y(M). Here rM∗r^*_M denotes the rank function of the dual matroid.

Cocircuit-rank conjecture. One has

rM∗(Y~(M))≤2.r^*_M(\widetilde{Y}(M))\le 2.

This conjecture generalizes the paper's principal theorem, which proves stronger conclusions for non-regular matroids and for regular matroids under specified minor hypotheses. The paper reports a theoretical reduction but says that the computational verification remains to be completed.

References

Primary source

João Paulo Costalonga, “Non-Separating Cocircuits and Graphicness in Matroids”, arXiv:1211.5823 (2012).

Progress summary

Refreshed
Open

No completed proof or counterexample has been found publicly; the original work reduced the conjecture to a computational check that was not completed.

Submitted on 25 November 2012, the original paper asks whether every 33-connected non-graphic binary matroid satisfies rM∗(Y~(M))≤2r^*_M(\widetilde{Y}(M))\le 2. Its theoretical reduction is conditional on a restricted computational verification, which the paper described as still being prepared.

Known results

  • For a 33-connected non-regular binary matroid, ∣Y~(M)∣≤1|\widetilde{Y}(M)|\le 1.
  • For regular matroids under the stated M∗(K3,3′′′)M^*(K_{3,3}^{\prime\prime\prime})-minor or M∗(K5)M^*(K_5)-minor hypotheses, Y~(M)=∅\widetilde{Y}(M)=\emptyset.
  • In those regular cases, respectively, E(M)=Y(M)E(M)=Y(M).
  • A binary 33-connected matroid with a PG(3,2)∗PG(3,2)^*-minor satisfies Y(M)=E(M)Y(M)=E(M); no later proof or counterexample was found.

Current status (as of September 2026): the conjecture remains open; only the original theoretical reduction and partial results are publicly recorded, with the required computational verification unreported.

Sources

Solutions 0

No solutions have been posted yet.