Roe–Strichartz theorem for iterated Laplacian sequences on symmetric spaces

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Let XX be the Riemannian symmetric space under consideration, let K/MK/M be its Furstenberg boundary, and let q′q' satisfy 1/q+1/q′=11/q+1/q'=1. Fix q∈(1,2)q\in(1,2), and let {fj}j∈N\{f_j\}_{j\in\mathbb N} be an infinite sequence of measurable functions on XX such that, for every j∈Nj\in\mathbb N,

Δfj=4ρ2qq′fj+1\Delta f_j=\frac{4\rho^2}{qq'}f_{j+1}

and, for a fixed p≥1p\geq1, there is a constant Cp>0C_p>0 depending only on pp such that

∥fj(⋅a)∥Lp(K)≤Cpϕiγqρ(a)\|f_j(\cdot a)\|_{L^p(K)}\leq C_p\phi_{i\gamma_q\rho}(a)

for all a∈A+‾a\in\overline{A^+}. Here γq=2/q−1\gamma_q=2/q-1 and PiγqρP_{i\gamma_q\rho} denotes the Poisson transform. Roe–Strichartz conjecture. Then

Δf0=−4ρ2qq′f0.\Delta f_0=-\frac{4\rho^2}{qq'}f_0.

Moreover, if p>1p>1, then f0(x)=PiγqρF(x)f_0(x)=P_{i\gamma_q\rho}F(x) for some F∈Lp(K/M)F\in L^p(K/M), while if p=1p=1, then f0=Piγqρμ(x)f_0=P_{i\gamma_q\rho}\mu(x) for some signed measure μ\mu on K/MK/M. This expected result would extend the known Roe–Strichartz phenomenon from established cases to the stated sequence and growth setting; the supplied source does not establish its resolution.

References

Primary source

Swagato K. Ray and Rudra P. Sarkar, “A theorem of Roe and Strichartz for Riemannian symmetric spaces of noncompact type”, arXiv:1207.6695 (2012).

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