Uncorrelatedness of nonincident arcs in uniformly random DAGs

From papers

Let G=(V,A)G=(V,A) be a directed acyclic graph, with arcs represented by indicator random variables AijA_{ij} and covariance matrix Σ\Sigma. Two arcs are incident when they share a common node. Uncorrelatedness conjecture. Arcs that are not incident on a common node are uncorrelated; equivalently, for distinct nodes i,j,k,li,j,k,l, COV(Aij,Akl)=0\mathsf{COV}(A_{ij},A_{kl})=0. This is supported by complete enumerations through seven nodes and simulations for larger DAGs, but no formal proof is given.

Progress summary

Open

No publicly documented progress on this conjecture was found.

No public discussion or published progress was found.

Current status (as of August 2026): The conjecture remains open, with no recorded proof, counterexample, or verified advance.

Sources & referencesView supporting material

Primary source

Marco Scutari, “On the Prior and Posterior Distributions Used in Graphical Modelling”, arXiv:1201.4058 (2012).

Solutions 1

Proof

The primary source's arc variables are signed trinomial variables, not Boolean edge-presence indicators. In the notation of its equation (4), set

Xij(G)={1,ij belongs to G,1,ji belongs to G,0,neither arc belongs to G,Xji=Xij.X_{ij}(G)= \begin{cases} 1,&i\to j\text{ belongs to }G,\\ -1,&j\to i\text{ belongs to }G,\\ 0,&\text{neither arc belongs to }G, \end{cases} \qquad X_{ji}=-X_{ij}.

Let GG be uniformly distributed over all labeled directed acyclic graphs on [n][n]. More generally, the following proof applies to every vertex-exchangeable distribution on directed graphs with no oppositely oriented parallel arcs.

For any distinct i,ji,j, the vertex transposition τ=(ij)\tau=(ij) preserves the distribution and satisfies

Xij(τG)=Xij(G).X_{ij}(\tau G)=-X_{ij}(G).

Consequently EXij=0\mathbb E X_{ij}=0. If i,j,k,li,j,k,l are distinct, the same transposition fixes XklX_{kl}. Therefore

E[XijXkl]=E[Xij(τG)Xkl(τG)]=E[XijXkl],\mathbb E[X_{ij}X_{kl}] =\mathbb E[X_{ij}(\tau G)X_{kl}(\tau G)] =-\mathbb E[X_{ij}X_{kl}],

and hence

Cov(Xij,Xkl)=0.\boxed{\operatorname{Cov}(X_{ij},X_{kl})=0.}

This proves Conjecture 3.1 for every nn; neither acyclicity nor uniformity is needed beyond vertex-exchangeability.

A stronger classification follows. Write M=(n2)M=\binom n2, v=EX122v=\mathbb E X_{12}^{2}, c=E[X12X13]c=\mathbb E[X_{12}X_{13}], and let BB be the oriented vertex-edge incidence matrix of the complete graph. Exchangeability and the vanishing just proved give

Σ=(v2c)IM+cBTB.\Sigma=(v-2c)I_M+cB^{\mathsf T}B.

Since BBT=nIn11TBB^{\mathsf T}=nI_n-\mathbf1\mathbf1^{\mathsf T}, the two covariance eigenvalues are v+(n2)cv+(n-2)c, with multiplicity n1n-1, and v2cv-2c, with multiplicity Mn+1M-n+1.

Source: M. Scutari, “On the Prior and Posterior Distributions Used in Graphical Modelling,” Bayesian Analysis 8 (2013), 505–532, equation (4) and Conjecture 3.1, doi:10.1214/13-BA819.

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