The conformal block inequality for symmetric divisors on \overline{M}_{0,9}

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Let g\mathfrak{g} be a simple Lie algebra. Let D:=Sym⁡D(g,ℓ,λ⃗)D:=\operatorname{Sym} D(\mathfrak{g},\ell,\vec{\lambda}) be a symmetrized conformal block divisor on M‾0,9\overline{M}_{0,9} associated to g\mathfrak{g}. The conformal block inequality. The divisor DD satisfies

D⋅F6,1,1,1≤3D⋅F5,2,1,1.D \cdot F_{6,1,1,1} \leq 3D \cdot F_{5,2,1,1}.

In particular, conformal block divisors do not cover the symmetric nef cone of M‾0,9\overline{M}_{0,9}.

References

Primary source

David Swinarski, “sl_2 conformal block divisors and the nef cone of M_0,n”, arXiv:1107.5331 (2011).

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