The asymptotic containment conjecture for tuples of standard Young tableaux

At least 17 years old · documented by

Let A1,…,AkA_1,\ldots,A_k be standard Young tableaux with sh⁡(Ai)=αi⊢ai\operatorname{sh}(A_i)=\alpha_i\vdash a_i for i∈[k]i\in[k]. Let Tn(A1,…,Ak)\mathcal{T}_n(A_1,\ldots,A_k) be the set of kk-tuples (T1,…,Tk)(T_1,\ldots,T_k) such that

sh⁡(T1)=⋯=sh⁡(Tk)\operatorname{sh}(T_1)=\cdots=\operatorname{sh}(T_k)

and Ti∈Tn(Ai)T_i\in\mathcal{T}_n(A_i) for all i∈[k]i\in[k]. Write E1=⋯=Ek=∅E_1=\cdots=E_k=\emptyset. Asymptotic containment conjecture.

lim⁡n→∞∣Tn(A1,…,Ak)∣∣Tn(E1,…,Ek)∣=fα1⋯fαka1!⋯ak!.\lim_{n\to\infty}\frac{|\mathcal{T}_n(A_1,\ldots,A_k)|}{|\mathcal{T}_n(E_1,\ldots,E_k)|}=\frac{f^{\alpha_1}\cdots f^{\alpha_k}}{a_1!\cdots a_k!}.

This generalizes the preceding one- and two-tableau asymptotic formulas: imposing the condition that all tableaux have the same shape is conjectured not to alter the limiting probability of simultaneous containment.

References

Primary source

Jang Soo Kim, “q-analog of tableau containment”, arXiv:0812.1256 (2010).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.