Transience conjecture for the natural prime-generating recurrence

Let a(n)a(n) be the sequence defined by the recurrence in the paper, and let n11n_1\geq 1 satisfy a(n1)1a(n_1)\geq 1. Transience conjecture. There exists an NN such that a(n)a(n1)a(n)-a(n-1) is 11 or prime for every n>Nn>N. The conjecture asserts that the states for which the local lemma does not apply are transient. It is motivated by computations showing non-prime values of the recurrence's gcd can occur initially, but suggesting that eventually every increment is 11 or prime.

Sources & referencesView supporting material

Primary source

Eric S. Rowland, “A natural prime-generating recurrence”, arXiv:0710.3217 (2008).

Progress summary

Refreshed
Open

No proof or counterexample has been reported; only special starting values are known to produce prime-or-one increments eventually.

Eric Rowland formulated the conjecture for the recurrence a(n)=a(n1)+gcd(n,a(n1))a(n)=a(n-1)+\gcd(n,a(n-1)). It predicts that exceptional non-prime increments are transient for every admissible initial state.

Known results

  • For a(1)=7a(1)=7, every increment from n2n\geq 2 is 11 or prime (Rowland).
  • Analogous results hold for some other initial values, including a(1)=4a(1)=4 and a(1)=8a(1)=8.
  • The stronger assertion that every increment is always 11 or prime is false: examples include g(18)=9g(18)=9 for a(1)=532a(1)=532 and g(21)=21g(21)=21 for a(1)=801a(1)=801.
  • A sufficient reduction is to show that some later ratio a(N)/Na(N)/N lies in {1,2,3}\{1,2,3\}, but no general proof is known.

Current status (as of August 2026): The conjecture remains open for general initial conditions; special cases and the failure of the stronger all-time claim are settled.

Sources

Solutions 0

No solutions have been posted yet.