Pierce–Birkhoff conjecture

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Fix an integer n≥1n \ge 1 and let A=R[x1,…,xn]A = \mathbb{R}[x_1,\dots,x_n]. A subset S⊆RnS \subseteq \mathbb{R}^n is semialgebraic if it is a finite union of sets of the form

{x∈Rn:p1(x)=⋯=pk(x)=0, q1(x)>0,…,ql(x)>0}\{x \in \mathbb{R}^n : p_1(x) = \cdots = p_k(x) = 0,\ q_1(x) > 0, \dots, q_l(x) > 0\}

with p1,…,pk,q1,…,ql∈Ap_1,\dots,p_k,q_1,\dots,q_l \in A.

Call a function h:Rn→Rh : \mathbb{R}^n \to \mathbb{R} piecewise polynomial if there exist finitely many closed semialgebraic sets P1,…,Pm⊆RnP_1,\dots,P_m \subseteq \mathbb{R}^n with Rn=⋃i=1mPi\mathbb{R}^n = \bigcup_{i=1}^m P_i and polynomials f1,…,fm∈Af_1,\dots,f_m \in A such that h(x)=fi(x)h(x) = f_i(x) for every ii and every x∈Pix \in P_i.

Then for every piecewise polynomial function h:Rn→Rh : \mathbb{R}^n \to \mathbb{R} there exist finite index sets II and JiJ_i (i∈Ii \in I) and polynomials gij∈R[x1,…,xn]g_{ij} \in \mathbb{R}[x_1,\dots,x_n] for i∈Ii \in I, j∈Jij \in J_i, such that

h(x)=max⁡i∈I min⁡j∈Ji gij(x)for all x∈Rn;h(x) = \max_{i \in I} \ \min_{j \in J_i} \ g_{ij}(x) \qquad \text{for all } x \in \mathbb{R}^n;

that is, the ring of piecewise polynomial functions on Rn\mathbb{R}^n coincides with the sublattice of RRn\mathbb{R}^{\mathbb{R}^n} generated by AA under the operations max⁡\max and min⁡\min.

Equivalent formulations 1Other wordings

Other statements of this same problem, merged from separate entries. Each is equivalent to the statement above — proving any one settles them all.

  1. The Pierce–Birkhoff conjecture for inf-sup definable functions

    Let n∈Nn\in\mathbb{N}. A function in PWP(Rn)PWP(\mathbb{R}^n) is a piecewise polynomial function on Rn\mathbb{R}^n, while ISD(Rn)ISD(\mathbb{R}^n) denotes the class of inf-sup definable functions introduced in the paper. Both are ff-rings, and ISD(Rn)⊆PWP(Rn)ISD(\mathbb{R}^n)\subseteq PWP(\mathbb{R}^n). Pierce–Birkhoff conjecture.

    ISD(Rn)=PWP(Rn).ISD(\mathbb{R}^n)=PWP(\mathbb{R}^n).

    The conjecture asserts that every piecewise polynomial function on Rn\mathbb{R}^n is inf-sup definable. The supplied text identifies this as the famous Pierce–Birkhoff conjecture but gives no resolution status.

    source: S. David Mis, Matti Lassas and Maarten V. de Hoop, “Semialgebraic Neural Networks: From roots to representations”, arXiv:2501.01564 (2025).

References

Primary source

Wikipedia

Additional references

  1. Wikipedia, Pierce–Birkhoff conjecture, the article this problem comes from.

Progress summary

Refreshed
Claimed solved

A September 2026 preprint claims to disprove the conjecture with an explicit example, but the result has not yet been independently verified.

The conjecture, first formulated by M. Henriksen and J. Isbell in the early 1960s, asserts that every piecewise-polynomial function can be built from polynomials using only maximum and minimum operations. The new claim would refute it in dimension 3030.

Known results

  • Lai and Lim (2025) proved the representation for continuous piecewise-polynomial functions on hyperplane partitions, for arbitrary degree and dimension; this is only a restricted case of the stated conjecture.

September 2026 counterexample

On September 9, 2026, the preprint Pierce-Birkhoff conjecture is false presented an explicit semialgebraic counterexample, which would settle the full conjecture negatively. A contemporaneous announcement says the counterexample was found with GPT and Claude models and checked by human experts, but the mathematical claim remains unrefereed and unconfirmed.

Current status (as of September 2026): The conjecture is claimed false by an explicit 3030-dimensional counterexample, while that counterexample has not yet received independent verification.

  • Claude Fable 5.1Anthropicsolved2026-09-09evidence

    Pierce–Birkhoff conjecture disproved

  • Claude Opus 5Anthropicsolved2026-09-09evidence

    Pierce–Birkhoff conjecture disproved

  • GPT-5.6 SolOpenAIsolved2026-09-09evidence

    Pierce–Birkhoff conjecture disproved

  • GPT 6OpenAIsolved2026-09-09evidence

    Pierce–Birkhoff conjecture disproved

Sources

Solutions 0

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