Erdős Problem #987 — Let x1,x2,…∈(0,1)x_1,x_2,\ldots \in (0,1) be an infinite sequence and let Ak=lim sup⁡n→∞∣∑j≤ne(kxj)∣,A_k=\limsup_{n\to \infty}\left\lvert \sum_{j\leq n} e(kx_j)\right\rvert, where e(x)=e2πixe(x)=e^{2\pi ix}.

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Let x1,x2,…∈(0,1)x_1,x_2,\ldots \in (0,1) be an infinite sequence and let Ak=lim sup⁡n→∞∣∑j≤ne(kxj)∣,A_k=\limsup_{n\to \infty}\left\lvert \sum_{j\leq n} e(kx_j)\right\rvert, where e(x)=e2πixe(x)=e^{2\pi ix}. Is it true that lim sup⁡k→∞Ak=∞?\limsup_{k\to \infty} A_k=\infty? Is it possible for Ak=o(k)A_k=o(k)?

References

Progress summary

Refreshed
Claimed solved

Both questions now have affirmative answers: the amplitudes must become unbounded, and a recent construction keeps them below roughly the square root of the index times its logarithm.

The problem is attributed to Erdős and was recorded as Problem 7.21 in 1974. It asks whether the exponential-sum amplitudes must be unbounded and whether some sequence can make them grow slower than linearly.

Known results

  • Erdős, 1964: established divergence and later proved A~k≫log⁡k\widetilde A_k\gg\log k for infinitely many kk.
  • Clunie, 1967: proved A~k≫k1/2\widetilde A_k\gg k^{1/2} for infinitely many kk, and constructed a sequence with Ak≤kA_k\le k for every kk.
  • Liu, 1969: under finitely many distinct points, proved Ak≫k1−ϵA_k\gg k^{1-\epsilon} infinitely often; Clunie observed that in fact Ak=∞A_k=\infty infinitely often.

April 2026 construction

A recent paper gives a sequence satisfying Ak≪klog⁡(2k)A_k\ll\sqrt{k\log(2k)} for every kk, hence Ak=o(k)A_k=o(k). A separate proof establishes the first question directly; the historical lower bound also implies unboundedness. The problem page additionally credits an internal OpenAI model with the construction, but this attribution is not independently corroborated there.

Current status (as of April 2026): both questions are settled affirmatively, with the stronger uniform bound Ak≪klog⁡(2k)A_k\ll\sqrt{k\log(2k)} and universal unboundedness established.

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