Erdős Problem #202 — Let n1<⋯<nr≤Nn_1<\cdots < n_r\leq N with associated ai(modni)a_i\pmod{n_i} such that the congruence classes are disjoint (that is, every integer is ≡ai(modni)\equiv a_i\pmod{n_i} for at most one 1≤i≤r1\leq i\leq r).

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Let n1<⋯<nr≤Nn_1<\cdots < n_r\leq N with associated ai(modni)a_i\pmod{n_i} such that the congruence classes are disjoint (that is, every integer is ≡ai(modni)\equiv a_i\pmod{n_i} for at most one 1≤i≤r1\leq i\leq r). How large can rr be in terms of NN?

References

Progress summary

Refreshed
Claimed solved

A recent AI-generated claim says the conjectured growth rate is proved, but no independent proof has yet verified it.

The problem asks for the largest number rr of pairwise-disjoint residue classes with distinct moduli at most NN. Erdős and Stein conjectured that the maximum f(N)f(N) satisfies f(N)=o(N)f(N)=o(N).

Known results

  • Erdős and Szemerédi (1968): established f(N)=o(N)f(N)=o(N) and gave initial upper and lower bounds.
  • Croot (2003): improved these to bounds involving L(N)=exp⁡(log⁡Nlog⁡log⁡N)L(N)=\exp(\sqrt{\log N\log\log N}).
  • Chen (2005), then de la Bretèche, Ford, and Vandehey (2013): obtained NL(N)−1+o(1)<f(N)<NL(N)−3/2+o(1)N L(N)^{-1+o(1)}<f(N)<N L(N)^{-\sqrt{3}/2+o(1)}.
  • De la Bretèche, Ford, and Vandehey conjectured that f(N)=NL(N)−1+o(1)f(N)=N L(N)^{-1+o(1)}.

Recent claimed proof

The problem history attributes a proof of f(N)=NL(N)−1+o(1)f(N)=N L(N)^{-1+o(1)} to GPT-5.4 Pro, prompted by Ho Boon Suan, using the Kahn–Kalai conjecture resolution. A recent arXiv paper says a preprint by Ho proves the conjecture, but the retrieved material supplies no independently checkable proof.

Current status (as of July 2026): The classical bounds and the conjectured order are established, while the claimed proof of f(N)=NL(N)−1+o(1)f(N)=N L(N)^{-1+o(1)} remains unverified.

Sources

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