Erdős Problem #956 — If C,D⊆R2C,D\subseteq \mathbb{R}^2 then the distance between CC and DD is defined by δ(C,D)=inf⁡c∈Cd∈D∥c−d∥.\delta(C,D)=\inf_{\substack{c\in C\\ d\in D}}\| c-d\|. Let h(n)h(n) be the maximal number of unit distances between…

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If C,D⊆R2C,D\subseteq \mathbb{R}^2 then the distance between CC and DD is defined by δ(C,D)=inf⁡c∈Cd∈D∥c−d∥.\delta(C,D)=\inf_{\substack{c\in C\\ d\in D}}\| c-d\|. Let h(n)h(n) be the maximal number of unit distances between disjoint convex translates. That is, the maximal mm such that there is a compact convex set C⊂R2C\subset \mathbb{R}^2 and a set XX of size nn such that all (C+x)x∈X(C+x)_{x\in X} are disjoint and there are mm pairs x1,x2∈Xx_1,x_2\in X such that δ(C+x1,C+x2)=1.\delta(C+x_1,C+x_2)=1. Determine h(n)h(n) - in particular, prove that there exists a constant c>0c>0 such that h(n)>n1+ch(n)>n^{1+c} for all large nn.

References

Progress summary

Refreshed
Claimed solved

A linked note claims the problem has been solved with the sharp growth rate, but the construction has not yet been independently verified.

Erdős and Pach asked for the maximum number of unit set-distances among pairwise disjoint translates of one planar compact convex set. The claimed stronger answer is that this maximum grows on the order of four-thirds powers of nn.

Known results

  • Erdős and Pach proved the upper bound h(n)=O(n4/3)h(n)=O(n^{4/3}).
  • Erdős and Pach proved the related upper bound O(n7/5)O(n^{7/5}) for arbitrary pairwise disjoint convex sets.
  • The elementary comparison h(n)≥f(n)h(n)\ge f(n) is recorded, where f(n)f(n) is the ordinary point-set unit-distance maximum.

Recent claimed solution

A linked note gives a parabolic-grid construction with nk=2k3+O(k2)n_k=2k^3+O(k^2) and Mk=512k4+O(k3)M_k=\frac{5}{12}k^4+O(k^3), claiming h(n)=Θ(n4/3)h(n)=\Theta(n^{4/3}). The discussion attributes the claim to GPT-5.5 Pro and Lean formalization to Aristotle, but notes that the disjointness and Euclidean unit-distance conversion beyond Valtr’s construction still require independent checking.

Current status (as of June 2026): The O(n4/3)O(n^{4/3}) upper bound is established, while a matching lower bound and hence h(n)=[0mΘ(n4/3)h(n)=[0m\Theta(n^{4/3}) remain an unverified claim.

Sources

Solutions 0

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