Erdős Problem #522 — Let f(z)=∑0≤k≤nϵkzkf(z)=\sum_{0\leq k\leq n} \epsilon_k z^k be a random polynomial, where ϵk∈{−1,1}\epsilon_k\in \{-1,1\} independently uniformly at random for 0≤k≤n0\leq k\leq n.

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Let f(z)=∑0≤k≤nϵkzkf(z)=\sum_{0\leq k\leq n} \epsilon_k z^k be a random polynomial, where ϵk∈{−1,1}\epsilon_k\in \{-1,1\} independently uniformly at random for 0≤k≤n0\leq k\leq n. Is it true that, if RnR_n is the number of roots of f(z)f(z) in {z∈C:∣z∣≤1}\{ z\in \mathbb{C} : \lvert z\rvert \leq 1\}, then Rnn/2→1\frac{R_n}{n/2}\to 1 almost surely?

References

Progress summary

Refreshed
Claimed solved

A 2021 result proves the expected half of the roots only in probability, while an unverified claim says the stronger almost-sure statement is true.

Erdős Problem #522 asks whether the proportion of roots inside the unit disk approaches one-half almost surely for random sign polynomials. The coefficient convention may be ambiguous between {−1,1}\{-1,1\} and {0,1}\{0,1\}; the {−1,1}\{-1,1\} version is the one treated as open.

Known results

  • Erdős and Offord (1956): the number of real roots is (2π+o(1))log⁡n\left(\frac{2}{\pi}+o(1)\right)\log n.
  • Yakir (2021): Rn=n/2+O(n9/10)R_n=n/2+O(n^{9/10}) in probability, proving Rn/(n/2)→1R_n/(n/2)\to1 in probability.

Quantitative almost-sure claim

A repository claims that Rn=n/2+O(n7/8+δ)R_n= n/2+O(n^{7/8+\delta}) almost surely for every δ>0\delta>0, which would solve the problem. This remains unverified: no retrieved preprint or peer-reviewed source corroborates it, and the formalization still uses sorry.

Current status (as of March 2026): the in-probability result is established, while the stronger almost-sure convergence has only an unverified claimed proof.

Sources

Solutions 0

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