Optimal exponent relating sumsets and difference sets

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Let AA be a finite subset of a commutative additive group ZZ, and define σ(A)=∣A+A∣∣A∣\sigma(A)=\frac{|A+A|}{|A|} and δ(A)=∣A−A∣∣A∣\delta(A)=\frac{|A-A|}{|A|}. The cited paper asks whether the exponent 12\frac{1}{2} in the inequality σ(A)1/2≤δ(A)\sigma(A)^{1/2}\leq\delta(A) can be improved. Equivalently, it asks whether there exists a universal exponent C<2C<2 such that σ(A)≤δ(A)C\sigma(A)\leq\delta(A)^C for every such AA.

References

Progress summary

Refreshed
Claimed solved

A July 2026 preprint gives explicit examples showing that the half-power bound cannot be strengthened, so the problem is resolved.

The problem asks whether the lower sum-difference inequality can hold with a uniformly stronger exponent. A 2026 construction shows that it cannot, even for finite subsets of the integers.

Known results

  • Penman and Wells established only the lower bound C≥log⁡(32/5)log⁡(26/5)=1.12594C\geq\frac{\log(32/5)}{\log(26/5)}=1.12594 (2014).
  • Staps proved the classical inequalities σ(A)1/2≤δ(A)≤σ(A)2\sigma(A)^{1/2}\leq\delta(A)\leq\sigma(A)^2 and characterized equality: only cosets of finite subgroups (2014).

July 2026 construction

For every positive even integer KK, the paper constructs explicit AK⊂ZA_K\subset\mathbb{Z} with C(AK)>2KK+3→2C(A_K)>\frac{2K}{K+3}\to2. Hence sup⁡AC(A)=2\sup_A C(A)=2, equivalently the least universal exponent in σ(A)≤δ(A)c\sigma(A)\leq\delta(A)^c is c=2c=2; the exponent 1/21/2 is optimal. A Lean formalization is provided. The construction and proof were developed with assistance from Hyra, based on the open-weights Hy3 model.

Current status (as of July 2026): The exponent 1/21/2 is settled as optimal, while the supremum is approached rather than attained for sets with at least two elements.

Sources

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