Erdős Problem #959 — Let A⊂R2A\subset \mathbb{R}^2 be a set of size nn and let {d1,…,dk}\{d_1,\ldots,d_k\} be the set of distinct distances determined by AA.

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Let A⊂R2A\subset \mathbb{R}^2 be a set of size nn and let {d1,…,dk}\{d_1,\ldots,d_k\} be the set of distinct distances determined by AA. Let f(d)f(d) be the number of times the distance dd is determined, and suppose the did_i are ordered such that f(d1)≥f(d2)≥⋯≥f(dk).f(d_1)\geq f(d_2)\geq \cdots \geq f(d_k). Estimate max⁡(f(d1)−f(d2)),\max (f(d_1)-f(d_2)), where the maximum is taken over all AA of size nn.

References

Progress summary

Refreshed
Claimed progress

A 2025 paper shows that the gap can grow at least like the number of points times its logarithm, but no matching upper limit is known.

Erdős asked how large the difference can be between the most common and second-most-common distances among nn planar points. The modern formulation maximizes this difference over all nn-point sets.

Known results

  • Clemen, Dumitrescu, and Liu (2025) proved a lower bound of Ω(nlog⁡n)\Omega(n\log n) for the maximum gap.

2025 lower-bound construction

Clemen, Dumitrescu, and Liu proved that, for sufficiently large nn and every 1≤k≤log⁡n1\le k\le\log n, some planar set satisfies ak(X)−ak+1(X)=Ω(nlog⁡n/k)a_k(X)-a_{k+1}(X)=\Omega(n\log n/k). The construction can prescribe the distances with the largest kk multiplicities.

Current status (as of March 2026): A lower bound of Ω(nlog⁡n)\Omega(n\log n) is established, but the correct order of growth and any matching upper bound remain open.

Sources

Solutions 0

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