Erdős Problem #1177 — Omitting finite triple systems at uncountable chromatic number

About 27 years old · traced to

For a finite triple system SS, consider triple systems that omit SS and have uncountable chromatic number. (a) If one exists, must one exist with cardinality at most 22ℵ02^{2^{\aleph_0}}? (b) If finite triple systems S1S_1 and S2S_2 can each be omitted by an uncountably chromatic triple system, must some uncountably chromatic triple system omit both? (c) If a κ\kappa-chromatic triple system omitting SS exists for some uncountable cardinal κ\kappa, must one exist for every uncountable cardinal λ\lambda?

References

Additional references

Some of Paul's favorite problems, problem booklet circulated at Paul Erdős and his mathematics, Budapest, July 1999.

Progress summary

Refreshed
Claimed solved

A 2026 preprint claims that every finite forbidden triple system has either no uncountable exact chromatic sizes or all of them, but the claim is not yet independently confirmed.

Erdős Problem #1177 asks which exact uncountable chromatic cardinalities can occur for systems avoiding a fixed finite triple system, and how different avoidance classes intersect. The recent formulation concerns exact chromatic number ℵ1\aleph_1 and extends to all uncountable cardinals.

2026 claimed resolution

A preprint claims the complete dichotomy

Spec⁡(F)=∅orSpec⁡(F)={λ:λ>ℵ0}.\operatorname{Spec}(F)=\varnothing\quad\text{or}\quad\operatorname{Spec}(F)=\{\lambda:\lambda>\aleph_0\}.

It reports the three clauses of Problem #1177 as yes, no, and yes: a witness at ℵ1\aleph_1 can have size at most 22ℵ02^{2^{\aleph_0}}; two specified forbidden systems—two triples sharing a pair and the loose 77-cycle—have nonempty individual classes but empty intersection; and existence at one uncountable cardinal implies existence at every uncountable cardinal. Version 2 states that the results were formally verified in Lean 4.

Current status (as of June 2026): A preprint claims to settle the exact-spectrum classification and all three clauses, but independent mathematical confirmation is still lacking.

Sources

Solutions 0

No solutions have been posted yet.