Erdős Problem #379 — Prime-power divisibility in binomial coefficients
Let be the largest integer such that, for every integer with , there is a prime (which may depend on ) for which divides the binomial coefficient . Prove that
References
Primary source
Additional references
Pinned Formal Conjectures source, Apache-2.0.
Progress summary
The question has been answered yes: binomial coefficients can have arbitrarily deep prime-power divisibility across every nontrivial position.
Erdős Problem asks whether the divisibility depth is unbounded along some sequence of integers . The problem is attributed to Erdős; the source does not state when it was posed.
Affirmative solution (date not stated)
Cambie, Kovač, and Tao proved the assertion, and a short elementary complete proof was subsequently obtained. For , choosing with gives ; hence . The argument shows every , , is divisible by either or . The discussion also records simpler constructions involving .
Current status (as of June 2026): The problem is resolved affirmatively; the complete proof establishes .
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Solutions 0
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