44 problems
Hyperbolicity conjecture. Every such group is hyperbolic.
Let be a one-relator group, and let denote the Baumslag–Solitar group for an integer . Gersten's conjecture. If cont…
Let be a hyperbolic one-relator group. Wise's conjecture. Every such group is virtually free-by-cyclic. If true, this would imply that every hyperbolic one-relator group admits…
Mel'nikov's conjecture. An infinite and residually finite Mel'nikov group is either a free group, a surface group or a solvable Baumslag--Solitar group.
Let be a one-relator group whose presentation complex has negative immersions. One-relator hyperbolization conjecture. The group is hyperbolic. The conjecture would imply t…
A strictly ascending HNN extension of a finite rank free group is an HNN extension , where is injective but not surjective. The groups un…
Let … A one-relator group is a group admitting a presentation with one defining relator. Gersten's conjecture. The group has the highest Dehn function among all one-rel…
Geometric presentation conjecture. The group is the fundamental group of an orientable 3-manifold if and only if is a geometric word.
Let denote the random model of two-generator one-relator groups whose defining relation is a commutator, and let be the probability that a group…
Let be the Baumslag-Gersten one-relator group … For a finitely generated group, the conjugator length function measures the smallest length of a conjugator between two conjugat…
The torsion-free cyclic relation-module conjecture. If is torsion-free and is cyclic as a -module, then is normally generated by a single elem…
Let be a free group, let , and let be the corresponding one-relator group. For a subset of , write…
Baumslag–Wise conjecture. Every one-relator group with torsion is virtually free-by-cyclic, and every hyperbolic one-relator group is virtually free-by-cyclic.
A group is coherent if every finitely generated subgroup is finitely presented. A one-relator group is a group admitting a presentation with one defining relator. Baumslag's conjec…
Let be a family of groups and let be their free product. For a fixed factor , let be an element of the free product that is…
Let be a nontrivial group, set , and let \savebox{\@brx}{m@th{langle}}% mathopen{copy@brxkern-0.5wd@brxusebox{@brx}} wsavebox{@brx}{\m@th{\rangle}…
Let be a group, let , and let be the standard projection to the factor. For , write \savebox{\@brx}{m@th{langle}…
Let and be torsion-free groups, set , and let \savebox{\@brx}{m@th{langle}}% mathopen{copy@brxkern-0.5wd@brxusebox{@brx}} wsavebox{@brx}{\m@th{\rangle}…
Let be a nontrivial group. Adding one generator and then one relator means forming a quotient of by the normal closure of an element. Kervaire's conjecture. T…
For each integer , let … The subgroup membership conjecture for . The subgroup membership problem is decidable in for every . The subgrou…
Louder--Wilton conjecture. Every one-relator group whose presentation complex has negative immersions is hyperbolic.
Infinite-index subgroup surface-group conjecture. Then is a surface group.
Surface Group Conjecture A. Let be a residually finite Mel'nikov group. Then is a surface group or for some non-zero integer .
Let be a special one-relator inverse monoid, with defining word . Decompose into its minimal invertible pieces using the Benoi…