16 problems
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Initial minors conjecture for detecting all nonzero minors
Let be a matrix. A set of initial minors is a set of minors of whose cardinality is bounded by a polynomial or a sub-exponential function in the size of…
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Brizolis's fixed-point conjecture for discrete logarithms
Let be prime. A primitive root modulo is an element generating . Brizolis's conjecture. There exist an integer and a primitive root…
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The conjecture on the error in estimated numbers of discrete logarithm fixed points
Let be prime, let and range over the parameters defining the fixed-point counting function, and let denote the c…
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Average auxiliary-count conjecture
Average auxiliary-count conjecture.
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Average fixed-point count conjectures
Average fixed-point conjectures.
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Relative-primitivity scaling conjectures for two-cycle counts
Relative-primitivity scaling conjectures.
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Two-cycle count conjectures from the auxiliary heuristic
Two-cycle count conjectures.
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Auxiliary solution-count conjectures for the discrete logarithm equation
Auxiliary solution-count conjectures.
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Two-cycle count conjectures for the discrete logarithm map
Two-cycle counting conjectures.
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Conjectures for fixed-point counts of the discrete logarithm map
Fixed-point counting conjectures.
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The large-order conjecture for Kummer field generators
Let be a prime power and let be a finite field. Let satisfy the conditions in Theorem, and suppose that . Large-order con…
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Conjectures for two-cycles with arbitrary and primitive-root conditions
Two-cycle counting conjectures. The paper conjectures
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Menezes–Teske–Weng's finite-field quadratic conjecture
Let , set , and let . Suppose that the quadratic equation … has two solutions . Menezes–Teske–Weng's…
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The stronger polynomial selection conjecture for small-characteristic DLP
Let be a finite field of odd characteristic. The polynomials are required to be coprime and have degree at most . Stronger polynomia…
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The conjectured difficulty of the discrete logarithm problem
Discrete logarithm problem conjecture. In well-chosen groups, computing from is conjectured to be very difficult, although exponentiation is very fas…
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Pollard's conjecture on the kangaroo method for powers of any integer
Pollard's conjecture. The same result as for powers of holds for powers of any integer under this assumption.