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Margulis–Zimmer conjecture on commensurated subgroups of S-arithmetic lattices
arXiv@arxiv
Margulis–Zimmer conjecture. Every commensurated subgroup of $\Lambda$ is either finite or $S'$ -arithmetic for some $S'\subseteq S$ .
Conjectureopenarithmetic-groups commensurated-subgroups lattices
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Margulis–Zimmer conjecture on commensurated subgroups of S-arithmetic lattices