9 problems
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Freedman's surgery conjecture for non-abelian free groups
Let the 4-dimensional topological surgery conjecture be the assertion that, for a 4-dimensional Poincaré pair , the sequence … is exact. In the link formulation, let…
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Disk embedding up to s-cobordism conjecture
Disk embedding up to s-cobordism conjecture. There should be an -cobordism of the immersion to a topological embedding.
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The nonexistence of a boundary-universal cork
Boundary-universal cork conjecture. There is no -universal cork.
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The universal cork conjecture
Universal cork conjecture. There is no universal cork, i.e. no cork relating every exotic pair of simply-connected, closed -manifolds.
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The disc embedding conjecture
Disc embedding conjecture. The circles bound disjointly embedded discs in with transverse spheres, inducing the same framing on as the .
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The topological 5-dimensional s-cobordism conjecture
-cobordism conjecture. There is a homeomorphism
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The topological surgery conjecture
Topological surgery conjecture. The map is topologically normally bordant rel. boundary to a homotopy equivalence if and only if the surgery obstruction in…
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The topological surgery conjecture for four-manifolds
Topological surgery conjecture. There exist a topological -manifold , with , and a homotopy equivalence extending :
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Hambleton–Teichner decomposition conjecture for smoothable 4-manifolds
Hambleton–Teichner decomposition conjecture. Every smoothable 4-manifold is topologically homeomorphic to a connected sum