OEIS A080170 conjecture

For every integer k2k\ge 2, the binomial-coefficient gcd quantity D(k)D(k) specified in OEIS A080170 satisfies D(k)=1D(k)=1 if and only if k+1ppart(k+1)>ppart(k+1)\frac{k+1}{\operatorname{ppart}(k+1)}>\operatorname{ppart}(k+1), where ppart(n)=max{pa:p is prime and pan}\operatorname{ppart}(n)=\max\{p^a:p\text{ is prime and }p^a\mathrel{\|}n\} is the largest exact prime-power component of nn.

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Progress summary

Refreshed
Solved

A June 2026 proof checked by computer in Lean resolves the conjecture, with no later error or challenge found.

OEIS A080170 conjectures an equivalence between a gcd condition on binomial coefficients and a condition involving the largest exact prime-power component of k+1k+1. The June 2026 preprint identifies this as conjecture (17) in Ralf Stephan’s collection and claims a proof for k2k \ge 2.

June 2026 formal resolution

The preprint proves D(k)=1(k+1)/ppart(k+1)>ppart(k+1)D(k)=1 \Longleftrightarrow (k+1)/\operatorname{ppart}(k+1)>\operatorname{ppart}(k+1), using finite differences, Lucas’ theorem, and base-pp arguments. The proof and Lean formalization are attributed to the MechMath Agent Team; the pinned source has no sorry, and the Formal Conjectures entry is marked research solved. No counterexample, error report, withdrawal, or retraction was found.

Current status (as of August 2026): The conjecture is resolved by a machine-checked Lean formalization, while the associated mathematical paper remains a preprint rather than a peer-reviewed publication.

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