Ma’s saturation-number conjecture
Ma’s saturation-number conjecture
Let . For every integer , there exists an integer such that, for every , , where is the minimum number of edges in an -vertex graph containing no cycle for , but such that adding any missing edge creates a copy of at least one such cycle.
Progress summary
A new paper disproves the conjecture once the forbidden cycle range includes length six, proves the length-six case exactly, and leaves longer ranges unresolved.
Ma’s conjecture predicts that, for every , the saturation number for the interval of cycles from through eventually equals .
Known results
- The exact formula was known for every positive integer .
19 August 2026 disproof for
The new paper proves a stronger upper bound with an -dependent subtraction, establishes exactly, and thereby disproves the conjectured eventual formula for every . It does not determine the exact saturation number for every .
Current status (as of August 2026): The conjecture is false for every , and the case is settled exactly; the exact values for all remain open.
Sources
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