Mahmoodian–Mirzakhani conjecture

For positive integers rstr\le s\le t, the complete tripartite graph Kr,s,tK_{r,s,t} admits a decomposition into 55-cycles if and only if rst(mod2)r\equiv s\equiv t\pmod{2}, rs+rt+st0(mod5)rs+rt+st\equiv 0\pmod{5}, and t4rsr+st\le \frac{4rs}{r+s}; that is, there is a collection C\mathcal{C} of 55-cycles such that E(Kr,s,t)E(K_{r,s,t}) is the disjoint union of the edge sets of the cycles in C\mathcal{C}.

Progress summary

Partially solved

A new paper proves the conjecture on its equality boundary and certifies 117 more cases, but the full conjecture remains open.

Mahmoodian and Mirzakhani posed the conjecture in 1995: for rstr \le s \le t, the necessary parity, divisibility, and size conditions for decomposing K(r,s,t)K(r,s,t) into 55-cycles should also be sufficient.

Known results

  • Equal part sizes: sufficiency was proved apart from the exceptional family K(5x,5x,z)K(5x,5x,z) with 5z5 \nmid z (Mahmoodian–Mirzakhani, 1995).
  • All part sizes even, and several cases with equal or suitably divisible parts, were settled (Cavenagh–Billington, 2011).
  • Further infinite families include all parts divisible by 55 under additional size restrictions (2019).
  • The odd, distinct-size case has remained the principal unresolved regime.

August 2026 boundary result

Bryant and Mačajová report a constructive proof of the equality-boundary case and computational certificates for 117 additional previously unresolved decompositions. Their preprint explicitly leaves the strict-interior cases open, so this is substantial partial progress rather than a solution of the conjecture.

Current status (as of August 2026): The equality-boundary case and 117 additional cases are settled in the new preprint, while the full conjecture for strict-interior triples remains open.

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